Accepted Answer
From Columb's Law which describe the electrostatic interaction.The formula is given and looks as follows [tex]F=k \frac{|q1*q2|}{r^{2} } [/tex]where:F is force acting between charges,q1 - charge one given in columbs,q2 - charge two given in columbs,r - distance between charge in metersk - constantFirst, we have to convert out formula to get r.[tex]F=k \frac{q1*q2}{r^{2} } [/tex]Now we multiplaty by [tex]r^{2} [/tex] both sides of equation[tex]F* r^{2} =k*|q1*q2|[/tex]Now we devide both sides by F[tex] r^{2} =k \frac{|q1*q2|}{F} [/tex]Next step is take square root[tex]r= \sqrt{k \frac{|q1*q2|}{F}} [/tex]We have all date, we can subsitute it to our formula [tex]r= \sqrt{k* \frac{|q1q2"}{F} } = \sqrt[2]{8.9* 10^{9* \frac{0.001*0.001}{200} }} = 6.67 [m][/tex]
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