Carlos pushes a 3 kg box with a force of 9 newtons. The force of friction on the box is 3 newtons in the opposite direction. What is the acceleration of the box?

The 'net' force acting on the box is (9 - 3) = 6 newtons in the direction that Carlos is pushing.Force = (mass) x (acceleration)6 = (3) x (acceleration)Divide each side by 3 :2 m/s² = acceleration

friction = 3 N pushing force= 9 Nas both are opposite in direction so their net force will be = 9-3= 6Nas we know thatF = ma re arranging the equationa = F/mby putting values a =  6/3 N/kga= 2 m/sec²