Is v2 = v1t+a dimensionally correct? Explain please!

See Answers (1)

Suggested Answer

you want v2 = v1 + atv is measured in m/s, a in m/s2, and t in s.the dimensions multiply like algebraic quantities. so because v2 is measured in m/s, then (v1 + at) has to come out in m/s the units for (v1 + at) are (m/s) + (m/s2)(s)time "s" cancels out one acceleration "s", so it comes ut to (m/s) + (m/s), which = (m/s). if you had (v1t + a), then you would have (m/s)(s) + (m/s2) which = (m) + (m/s2), which doesn't work.

Related Question in Physics