Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

V2^2 = V1^2 + 2*a* sV2 = final velocityV1 = initial velocitya   = accelerations   = displacement covered25^2 = V1^2 + 2 * 1.2 * 200625  = V1^2  + 480625 - 480 = V1^2145          = V1^2So V1 = Sqrt(145) = 12.04 m/s