A stone thrown horizontally at a speed of 5m/s from the top of a cliff 78.4m high.
A. How long does it take the stone to reach the bottom of the cliff?
B. How far from the base of the cliff does the stone strike the ground?

a) It will take 4 seconds to reach the bottom of the cliffb) The stone strike at a distance of 20 m from the bottom of the cliffWhat is equation of motion?It is an equation that describe the behavior of a physical system in terms of its motion as a function of timeusing equation of motionsince, it is thrown initial horizontally at a speed of = 5m/sinitial vertical velocity = 0 s = u t + 1/2g(t^2)78.4 = 1/2 * 9.8 * (t^2)t^2 = (78.4 *2)/9.8t = (16)^(1/2)t= 4seca) It will take 4 seconds to reach the bottom of the cliffb) distance from the base of cliff stone strike = horizontal velocity * time                                                                                5 m/s * 4 second                                                                                 20 mhence , the stone strike at a distance of 20 m from the bottom of the clifflearn more about equation of  motion https://brainly.com/question/13514745?referrer=searchResults#SPJ2

A) t=?h = v1(y direction) *t +1/2 g*tt78.4=0 *t + 1/2*9.8*tt78.4 = 0+ 4.9 tttt=t(squqre) =78.4/4.9 =16so t = sqrt16 =4 sec. the time needed to hit the ground.B) how far =x =? x =v(horizontal) *t =5*4 =20 m.