In an 8.00 km race, one runner runs at a steady 11.0 km/h and other runs at 14.8 km/h. How far from the finish line is the slower runner when the fast runner fisnishes the race?

the fast runner will cover 8 km by time = t = d/v =8/14.8 = 0.54 hourat that time ( 0.54 hr ) the slower runner would  cover d = v*t = 11*.0.54 = 5.94 kmSo the slower would be at a distance = 8km - 5.94km =2.06 km from the finish line.