a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500m/s^2. what is the velocity of the stroller after it has traveled 4.75m? 

You're going to use the constant acceleration motion equation for velocity and displacement:(V)final²=(V)initial²+2a(Δx)Given:a=0.500m/s²Δx=4.75m(V)intial=0m(V)final= UNKNOWN(V)final= 2.179m/s

Hello!A person pushing a stroller start from rest uniformly accelerating at a rate of 0.500 m/s². What is the velocity of the stroller after it traveled 4.75 m ?We have the following data:a (acceleration) = 0.500 m/s²Vf (final velocity) = ? (in m/s)Vi (initial velocity) = 0 m/sΔx (displacement) = 4.75 mSolving:Let's apply the Torricelli Equation, to find the velocity of the stroller, let's see:[tex]V_f^2 = V_i^2 + 2*a*\Delta{x}[/tex][tex]V_f^2 = 0^2 + 2*0.500*4.75[/tex][tex]V_f^2 = 0 + 4.75[/tex][tex]V_f^2 = 4.75[/tex][tex]V_f = \sqrt{4.75}[/tex][tex]\boxed{\boxed{V_f \approx 2.18\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}[/tex]Answer:The velocity of the stroller is approximately 2.18 m/s________________________________[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]