A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?

The equation v²=u²+2as will help with solving this equationv is what we are trying to findu=0a=4.9s=200v²=0²+2*4.9*200v=√(2*4.9*200)v=√1960v=44.3 m/s (3 sf)

Hello!A race car starting from rest accelerates uniformly at a rate of 3.90 m/s² what is the cars speed after it has traveled 200 m.We have the following data:Vf (final velocity) = ? (in m/s)Vi (initial velocity) = 0 m/s (accelerated from rest)d (displacement) = 200 ma (acceleration) = 4.90 m/s²Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:[tex]V_f^2 = V_i^2 + 2*a*d[/tex][tex]V_f^2 = 0^2 + 2*4.90*200[/tex][tex]V_f^2 = 0 + 1960[/tex][tex]V_f^2 = 1960[/tex][tex]V_f = \sqrt{1960}[/tex][tex]V_f = 44.27188724...[/tex][tex]\boxed{\boxed{V_f \approx 44.27\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}[/tex]________________________________[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]