Accepted Answer
Pressure under water is called the gauge pressure.[tex]Pressure= \frac{Force}{Area} \\ F=mg \\ P= \frac{mg}{A}[/tex]Now the next part is difficult to put into an equation because you need the symbol for density, which is ρ, pronounced rho. I cannot type ρ into the equation so I will use p.[tex]p= \frac{m}{V} [/tex] (m=mass, V=Volume)[tex]m=pV \\ P= \frac{pVg}{A} \\ V=Ah[/tex]A=Area of the base of the object, or cylinder of water above the object, h= height of object[tex]P= \frac{p(Ah)g}{A} [/tex]The "A"s cancel, leaving us with[tex]P=pgh[/tex]You are only looking for the water pressure, so you would not be concerned with atmospheric pressure on top of that.[tex]P_{gauge} =p_{liquid} g h_{object} [/tex]The density of water is [tex]1000 \frac{kg}{ m^{3} } [/tex]Use 1000 for ρGravity is 9.8Height is 220[tex]P=pgh \\ P=1000*9.8*220 \\ P=2.16*10^{6} Pa[/tex](Pa is Pascals, the unit for pressure)
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