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A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 N and 1510 N, respectively. The acceleration of the cable is 0.620 m/s^2, upward. What is the tension in the cable above the worker (the worker is above the crate, not touching it)?

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Suggested Answer

Since resultant force = mass * acceleration, [tex]T-2475 = 0.620*mass[/tex]mass = [tex] \frac{2475}{9.8} = 252.5...[/tex]therefore [tex]T=(0.620*252.5...)+2475=2631.55... = 2630N (3sf)[/tex]

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