A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

[tex]u = 30ms^{-1}
\\t = 0.75s
\\a = 9.8ms^{-2} (Gravity)
\\s = ?[/tex][tex]s = ut + \frac{1}{2}at^2
\\s = (30)(0.75)+ \frac{1}{2}(9.8)(0.75)^2
\\s = 22.5 + 2.75625
\\s = 25.25625[/tex]s = 25.3 m (3 sf)