a 0.4 kg block rests on a desk. the coefficient of static friction is 0.2. You push the side of the block but do not have a spring scale to measure the force you use. the block does not move. which statement is true about the force of static friction?

Answer:D. It is no smaller than [tex]0.78N[/tex]Explanation:The question is incomplete. These are all the options : A. It is no larger than [tex]0.78N[/tex]B. It is [tex]0.78N[/tex]C. It is [tex]0.08N[/tex]D. It is no smaller than [tex]0.78N[/tex]To solve this problem, we have the data of : [tex]m=0.4kg[/tex]Where ''m'' is the mass of the blockμ = 0.2Where ''μ'' is the coefficient of static frictionIf we want to find the magnitude of the force of static friction we need to use the following equation : [tex]F_{sf}=[/tex] μ.[tex]F_{N}[/tex] (I)Where ''[tex]F_{N}[/tex]'' is the normal force that the desk exerts on the block. Its magnitude is equal to the weight (because we suppose that the block rests horizontally on the desk). The weight ''[tex]W[/tex]'' can be calculated as : [tex]W=m.g[/tex]Where ''m'' is the mass and ''g'' is the acceleration due to gravity. The value of ''g'' is [tex]g=9.81\frac{m}{s^{2}}[/tex]The weight of the block is [tex]W=(0.4kg).(9.81\frac{m}{s^{2}})[/tex][tex]W=3.924N[/tex]Now, the weight is equal to the normal force ⇒[tex]W=F_{N}=3.924N[/tex]Using the equation (I) : [tex]F_{sf}=(0.2).(3.924N)[/tex][tex]F_{sf}=0.7848N[/tex]The correct option is D. It is no smaller than [tex]0.78N[/tex]

Static friction is greater than Applied force