Accepted Answer
Answer: 5.047m/s Explanation:Initial velocity (U) = ?Height (s) = 1.3mTime taken (t) =?g = acceleration due to gravity = 9.8m/s²From equation of motion;S = ut - ½gt².........equation (i) (note the negative sign is because the Hooper is moving against gravity).Velocity at maximum height = 0V = u - gt ........ equation (ii)0 = u - gt t = u/gPut t = u/g into equation (i)S = u(u/g) - ½g(u/g)²S = u²/g - ½u²/gS = ½u²/g2S = u²/gU² = 2SgU² = 2 * 1.3 * 9.8U² = 25.48 U = 5.047m/s (take square root of U²)
Suggested Answer
the velocity the hopper jumped at was 4.9 miles per hour
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