[SOLVED] For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given by E=1/2kx^2 where k is the elastic spring constant and x is the extension.

The average force can be calculated as F/2, whereF = kxTherefore, substituting this in to the equation for energy:Energy = Force * DistanceEnergy = F/2 * xEnergy = kx/2 * xEnergy = 1/2 kx^2

For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given by
E=1/2kx^2
where k is the elastic spring constant and x is the extension.

Accepted Answer

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