A 33 kg gun is standing on a frictionless surface. The gun fires a 57.7g bullet with a muzzle velocity of 325m/s. The positive direction is that of the bullet.
Calculate the kinetic energy of thebullet immediately after the gun was fired. Answer in units of J

The Kinetic Energy of the bullet of mass 57.7 g immediately after firing the gun with muzzle velocity of 325m/s is - 3047.28 joules.What is Kinetic Energy of a body?The energy possessed by a body due to its motion (velocity) is called its kinetic energy. Mathematically -E [K] = 1/2mv²Given is a gun that fires a 57.7g bullet with a muzzle velocity of 325m/s. We can calculate the kinetic energy from the formula discussed above as -E[K] = 1/2mv²Mass of bullet = [M] = 57.7 g = 0.0577 KgVelocity of bullet = [v] = 325 m/sPutting values -E[K] =  1/2mv²E[K] = 0.5 x 0.0577 x 325 x 325E[K] = 3047.28 joules.Therefore, the Kinetic Energy of the bullet of mass 57.7 g immediately after firing the gun with muzzle velocity of 325m/s is - 3047.28 joulesTo solve more questions on Kinetic energy, visit the link below-brainly.com/question/10703924#SPJ2

Kinetic Energy =  (1/2) mv^2.m = 57.7 g = 57.7/1000 = 0.00577 kg.v = 325 m/s.E = 0.5 * 0.00577 * 325^ 2.    Use your calculator.E = 304.728125  J.That's the kinetic energy.