What is the gravitational force acting on a 70.0 kg object standing on the earth's surface ?

g( gravitational acceleration)=-9.81 m/s^2 m(mass) = 70.0 kgAccording to Newton's second law of motion: "F=ma"Force is equal mass per acceleration therefore W=mgThis is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g" is gravitational accelerationTherefore:W= mg W= (70.0 kg) (-9.81m/s^2)W= -686.7 N* The "N" means newton which is (kg* m/s^2)