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If F(X)= 6X-4 and F(A)= 26 what is the value of a? Explain?

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Accepted Answer

[tex]F(X)=6X-4 \hbox{ and } F(A)=26 \\
\hbox{substitute A for X:} \\
F(A)=6A-4 \\
26=6A-4 \\
26+4=6A \\
30=6A \\
\frac{30}{6}=A \\
\boxed{A=5}[/tex]

Suggested Answer

26=6a -430 = 6am(Divide both sides by 6)A = 5

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