Accepted Answer
I don't see a table anywhere near here, but I think I can show you how to calculate those quantities.From your description, I'm picturing two 32-ohm resistors in parallel, connected across a 96-volt battery or other power supply.In parallel, each resistor has the same voltage across it. So it might be easier if we begin by considering them separately:Current through one resistor = V/R = 96/32 = 3 Amperes.Current through both of them, supplied by the battery = 6 Amperes.Power dissipated by one resistor = I² R = (3)² (32) = 9 x 32 = 288 watts.Power dissipated by both of them, supplied by the battery = 576 watts.Equivalent resistance as seen by the battery = (32)² / 64 = 16 ohms. Check:If the battery sees 16 ohms, then the current is V/R = 96/16 = 6 Amp.Power supplied by the battery is (V x I) = 96 x 6 = 576 watts.yay !Note:288 watts is a lot of power. You'll need big, expensive resistors,possibly even immersed in an oil bath, unless your resistors arecoils of resistive wire and you plan on toasting bread with them.
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