not sure if this is a physics question but how do I find the formula using
ohms law..any one

Physics is as good a place as any, I guess.And, before we roll up our sleeves, may I also note that assigning 48 fill-ins(4 each for 12 problems) is exceeded in its excess only by expecting all of the answers in return for 5 points.    I'll give you the tips and hints you need in order to solve these, and then I'll wish you well.I see from the label in the upper corner that all of this refers to series circuits.That's important to know, and I was about to ask.  So we're going to assumethat for the whole bunch on the page, R1 and R2 are in series, connected across VS, and there are no other components involved besides the two resistors.OK.  Here are the tools you need:On a resistor . . .                             ' K ' = 'thousand'                         ' Meg ' = 'million'Total resistance . . . RT = R1 + R2 ohmsVoltage across each resistor:                                                  VR1 = VS  [ R1 / (R1+R2) ]    volts                                                  VR2 = VS [ R2 / (R1+R2) ]     voltsTotal current in the series circuit:                                                       IT = VS / RT  = VS / (R1+R2)  AmpsAnd that's it. Easier than I thought.  There are some other things that it could have asked for, but it didn't. Example:  Line #4:VS = 5 voltsR1 = 470 ohmsR2 = 1,000 ohmsRT = R1 + R2 = 1,470 ohmsVR1 = VS ( R1/RT ) = 5 (470 / 1,470) = 1.598... voltsVR2 = VS ( R2/RT ) = 5 (1,000 / 1,470) = 3.401 volts(Notice that  VR1 + VR2 always = VS.)IT = VS / RT = 5 / 1,470 = 0.0034 Amperes = 3.4 mA (milliamps)The power supplied by the battery is  (VS)²/RT = 0.017 watt ,but it doesn't ask for that.And that's it !  That's everything you need.  Go get 'em, champ !