What is the volume of a 3.00M(mol/L) solution made with 122g of LiF?

1.567  L is the volume of a 3.00M(mol/L) solution made with 122g of LiF. Define molarity of a solution.Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]Firstly calculate the moles of  LiF.Moles = [tex]\frac{mass}{molar \;mass}[/tex]Moles = [tex]\frac{122g}{25.94}[/tex]. (25.94 is the molar mass of LiF)Moles = 4.703Now find the volume:[tex]Molarity = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex][tex]3.00M = \frac{4.703}{Volume \;of \;solution \;in \;litre}[/tex]V = 1.567 LHence, 1.567 L is the volume of a 3.00M(mol/L) solution made with 122g of LiF.Learn more about molarity here:https://brainly.com/question/2817451#SPJ2

moles is equal to mass over molar mass122g/25.94 (25.94 is the molar mass of LiF)3 = (4.703/L)L = 1.567