14 1/4 - 10 3/7 Reduce to lowest form....
step by step to see if my answer your answer

[tex]14 \frac{1}{4}= \frac{14\cdot4+1}{4}= \frac{57}{4} [/tex][tex]10 \frac{3}{7}= \frac{10\cdot7+3}{3}= \frac{73}{7} [/tex][tex]\hbox {So, you have now } \frac{57}{4}-\frac{73}{7}=\frac{57\cdot7}{4\cdot7}-\frac{73\cdot4}{7\cdot4}= \frac{399}{28}-\frac{292}{28}=\boxed {\frac{107}{28} } [/tex][tex]=\boxed { 3\frac{23}{28} }[/tex]

make them improper fractions:14 1/4 would be 57/410 3/7 would be 73/7Make them the same common denominator:Times 57/4 by 7/7 =399/28Times 73/7 by 4/4 =292/28Now subtract them:107/28 Now Simplify:107/28= (3*28+23)/28=3+23/28= 3 23/28The Answer:3 23/28