Could someone help me out please I don’t know how to

As per given by the question,There are given that ,[tex]4y^2+y-9,\text{ when y=-3}[/tex]Now,There are given y=-3.So,Substitute the value -3 instead of y in given equation,Then,From the equation,[tex]4y^2+y-9[/tex]Put the value of y in given equation,[tex]4y^2+y-9=4(-3)^2+(-3)-9[/tex]Now, solve the above equation,[tex]\begin{gathered} 4y^2+y-9=4(-3)^2+(-3)-9 \\ =4(9)-3-9 \\ =36-3-9 \\ =36-12 \\ =24 \end{gathered}[/tex]Hence, the value of given equation is 24.