the perimeter of the original rectangle is 16 ft. what is the perimeter of the enlarged rectangle? round to the nearest tenth if necessary.

To calculate the perimeter of the enlarged rectangle, we need to get the breadth first.The original rectangle is similar to the enlarged rectangle, so the ratio of thier corresponding sides must be equalLet b represent the breadth of the enlarged rectangle,[tex]\begin{gathered} \text{ Ratio of corresponding sides is given as } \\ \frac{1.8}{b}=\frac{6.2}{12.4} \\ \text{cross multiply} \\ 6.2b=12.4\text{ x 1.8} \\ 6.2b=22.32 \\ b=\frac{22.32}{6.2} \\ b=3.6\text{ ft} \end{gathered}[/tex]Now, the length of the enlarged rectangle is 12.4ft while the breadth is 3.6ftThe perimeter = 2(L+B)= 2(12.4 + 3.6)=2(16)=32ftThe perimeter of the enlarged rectangle is 32 ft