solve the system of linear equations by substitution 3y=-2x and y=x-5

Step 1Given;[tex]\begin{gathered} 3y=-2x--(1) \\ y=x-5--(2) \end{gathered}[/tex]Required; To solve the system of linear equationsStep 2Find the value of y and x[tex]\begin{gathered} Substitute\text{ 2 into 1} \\ 3(x-5)=-2x \\ 3x-15=-2x \\ 5x=15 \\ \frac{5x}{5}=\frac{15}{5} \\ x=3 \end{gathered}[/tex][tex]\begin{gathered} From\text{ 2, y=x-5} \\ y=3-5=-2 \end{gathered}[/tex]Answers;[tex]x=3,\text{ y=-2}[/tex]