Supposed to 25% of the time Danny eat out twice a month 30% of the time he eats out once a month and 45% of the time he doesn’t eat out at all in a given month what is the expected value for the number of times daily eats out during a month

AnswerExpected value = 0.8 times per monthExplanationThe mean of the probability distribution is called expected value and it is given asE(X) = Σxᵢpᵢwherexᵢ = each variable = Number of times Danny eats outpᵢ = probability of each variablen = number of variablesp = probability of one variableWe need to set up the probability distribution firstxᵢ | pᵢ2 | 0.251 | 0.300 | 0.45E(X) = (2 × 0.25) + (1 × 0.30) + (0 × 0.45)= 0.5 + 0.3 + 0= 0.8Hope this Helps!!!