a wrecking ball is suspended from a 5.0 m long cable that makes a 30o angle with the vertical. the ball is released and swings down. what is the ball's speed at the lowest point?

The speed of ball at the lowest point is 7m/s.We are given that,The cable length is = L = 5.0mThe inclination angle with respect to the vertical = 30°Thus, the conservation of energy can be used to address the given issue. The wire from which the ball is suspended is slanted vertically. Consequently, the ball's height increase is,h = Lsinθh = 5.0m(sin 30°)h = 5/2m = 2.5mNow, at the lowest position, the ball's kinetic energy (KE) will be the highest, and at the highest point, the ball's potential energy will be the highest ( PE). then, in accordance with energy conservation.Potential energy at the greatest point equals kinetic energy at the lowest.K.E = P.E1/2mv² =mghv² = 2ghv² = 2 (9.8m/s²)(2.5m)v² = 49m/sv = 7m/sThus, the speed of ball at the lowest point would be 7m/s.To know more about speedhttps://brainly.com/question/3257219#SPJ4