a flatbed truck is carrying a heavy crate. the coefficient of static friction between the crate and the bed of the truck is 0.75. what is the maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck?

A flatbed truck is carrying a heavy crate. the coefficient of static friction between the crate and the bed of the truck is 0.75. The maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck will be 7.35 [tex]m/s^{2}[/tex]Static friction force = mu * Nmu = coefficient of static frictionN = normal m = massg = acceleration due to gravity  Static friction force = 0.75 * m * g = 7.35 * m  N 7.35 * m  Newton  is the maximum force , above which the crate will start to move Force = mass * acceleration7.35 * m = m * aa = 7.35 [tex]m/s^{2}[/tex]The maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck will be 7.35 [tex]m/s^{2}[/tex]To learn more about static friction here :https://brainly.com/question/13000653#SPJ4