a man pushes an 80-n crate a distance of 5.0 m upward along a frictionless slope that makes an angle of 30 with the horizontal. his force is parallel to the slope. if the speed of the crate decreases at a rate of 1.5 m/s^2, then the work done by the man is

A man pushes an 80-n crate a distance of 5.0 m upward along a frictionless slope that makes an angle of 30 with the horizontal. his force is parallel to the slope. if the speed of the crate decreases at a rate of 1.5 m/s^2, then the work done by the man is 138.775 JF net = 0m*g*sin(theta) = weight force in the direction parallel to motionF (applied ) - m*g*sin(theta) = mass * accelerationF (applied ) = 80/9.8 * (-1.5) + 80* sin(30) = - 12.24 + 40 = - 27.755 Nwork done = force * displacement                   = 27.755 * 5 = 138.775 JThe work done by the man is 138.775 JTo learn more about work done here :https://brainly.com/question/13662169#SPJ4