when the sledder slides to the top of the left hill (shown in the figure below), her speed is 6.5 m/s. the total mass of the girl and the sled is 55 kg. she continues sliding down, passes the valley and moves up on the right hill. what is the speed of the sledder at the top of the right hill assuming a thermal energy of 160 j is generated due to friction during the sliding process?

The speed of the sledder at the top of the right hill assuming a thermal energy of 160 j is generated due to friction during the sliding process is 1.8 m / sAccording to law of conservation of energy,m1 g h1 + 1 / 2 m1 v1² = m2 g h2 + 1 / 2 m2 v2² m1 = m2 = mm g h1 + 1 / 2 m v1² = m g h2 + 1 / 2 m v2² - WW is included because there is some energy lost as heat.g = 9.8 m / s²h1 = 4.2 mv1 = 6.5 m / sh2 = 5.9 mH = 160 Jm = 55 kgg h1 + 1 / 2 v1² = g h2 + 1 / 2 v2² + W / m( 9.8 * 4.2 ) + ( 1 / 2 * 6.5² ) = ( 9.8 * 5.9 ) + ( 1 / 2 * v2² ) + ( 160 / 55 )41.16 + 21.13 = 57.82 + v2² / 2 + 2.91v2² = 1.56 * 2v2 = 1.8 m / sTherefore, the speed of the sledder is 1.8 m / sTo know more about law of conservation of energyhttps://brainly.com/question/12050604#SPJ4