speedy sue, driving at 33.0 m/s, enters a one-lane tunnel. she then observes a slow-moving van 165 m ahead traveling with velocity 5.40 m/s. sue applies her brakes but can accelerate only at -2.00 m/s2 because the road is wet. will there be a collision?

Yes, there will be collision. The collision will be occur after time,  t = 8.75619s.The formula for calculating the position of a moving item in a straight line:x = x₀ + v₀· t + 1/2 · a · t²Wherex = position at time tx₀ = initial positiont = timev₀ = initial velocitya = accelerationIf object moves with constant speed, then a = 0 and x = x₀ + v · tx Sue = x vanx₀+ v₀ · t + 1/2 · a · t² = x₀+ v · t   (x₀ Sue = 0, x₀ van = 160 m)33 m/s · t - 1/2 · 2 m/s² · t² = 165m + 5.40 m/s · t33m/s t - t²  = 165m + 5.40 m/s t t² - 33m/s t + 5.40 m/s t + 165m = 0 t² - 27.6m/s  +165m = 0 on solving this quadratic equation we get :t = 18.8438st = 8.75619swe take the lower one because there will only be one collision.Yes, there will be collision. The collision will be occur after time,  t = 8.75619s.To know more about accelerationhttps://brainly.com/question/13096653#SPJ4