if the speed of a car is increased by 70%, by what factor will its minimum braking distance be increased, assuming all else is the same? ignore the driver's reaction time.

Using concepts of Kinetic Energy, we got that 2.89 times of previous braking distance we need to increase to stop the car.We have Speed of car = vNow, when speed is increase by 70%,in that casenew speed of car v'= 1.7 vWe know that K.E=(1/2)×m×v²,where m is the mass of the object and v is the velocity of the object.Now, when speed is increase by 70% then,new Kinetic Energy is =(1/2)×m×(1.7)²New kinetic energy=    (1.7)²K.E₁New kinetic energy=2.89K.E₁Hence, to stop the car we need to increase our braking distance to 2.89 times from the previous braking distance.To know more about Kinetic Energy, visit here:https://brainly.com/question/12669551#SPJ4;