a rifle bullet with a mass of 12.0 g traveling toward the right at 260 m/s strikes a large bag of sand and penetrates it to a depth of 23.0 cm. determine the magnitude and direction of the friction force (assumed constant) that acts on the bullet.

The magnitude of the friction force is 1.76x10⁵N in the negative direction ( the direction opposite to the motion of the bullet)To find the magnitude and direction of force, apply the following conceptm (mass) =12.0∗10⁻³ kgv₁ ( initial velocity)=260m/sv₂ ( final velocity)=0x( depth)=0.230m,v₂² =v₁ ²+2axa= –1.47∗10⁵ m/s²According to Newton’s second law ∑F  =ma f ( kinetic friction) =ma=–1.76∗10⁵ NTherefore, the (kinetic) friction force is 1.76∗10⁵ N in the negative x direction.To learn more about friction force, visit https://brainly.com/question/20383236#SPJ4