tarzan grabs a vine hanging vertically from a tall tree when he is running at 9.0m/s. (a) how high can he swing upward? (b) does the length of the vine affect this height?

The highest height is equal to 9 meters per second squared over two times the speed of 9.8 meters per second squared, or 4.1 meters above the lowest point.We have a lengthy wine. Currently, the margin is originally moving in a horizontal direction at a speed of 1 (which is 9 meters per second), at which point it captures the vine at its highest point. The height above the lowest position is in the ultimate position of the Tarzan above the initial position, and at the maximum height, the final speed v 2 will equal 0. We must ascertain the highest point. It is possible to consult mechanical energy. The mechanical energy used in motion equals the mechanical energy used in motion. Therefore, if we assume that the gravitational potential energy is 0, then the initial energy is in the form of kinetic energy when the wine is vertical.M times V divided by half. At the highest point, the kinetic energy is zero, the potential energy is m g times hint, and the potential energy is zero. So, we get. V1 squared over 2g is the expression for the maximum height. Equation then is this. 1. For the first component, we can state that the highest height is equal to 9 meters per second squared above twice the rate of 9.8 meters per second squared, or 4.1 meters above the lowest position. Then split. The maximum height is independent of vine length.To know more about energy click here:https://brainly.com/question/11399976#SPJ4