4)a heat pump used to heat a house runs about one-third of the time. the house is losing heat at an average rate of 22000 kj/h. if the cop of the heat pump is 2.8, determine the power the heat pump draws when running.

Using concepts of heat pump, we got 6.55kj/kg is the power the heat pump draws when running.A heat pump is basically a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building.To, solve this question we have to assume that the heat pump is at steady stateLet,Q₁ = 22000 kj/kgCOP = 2.8Since heat pump used to heat a house runs about one-third of the time.So,Q₁ = 3×(22000) = 66000 kj/kgWe known the formula for cop of heat pump which is as follow:COP = Q₁/ω2.8 = 66000 / ωω = 66000 / 2.8ω = 6.66 kj/kgHence the power that heat pump draws when running will be 6.55 kj/kgTo learn more about heat pump, visit here:brainly.com/question/1042914#SPJ4