the magnetic field perpendicular to a circular wire loop 6.0 cmcm in diameter is changed from 0.60 tt to -0.65 tt in 120 msms , where means the field points away from an observer and - toward the observer. part a calculate the induced emf.

Using the concepts of Faradays Law, we got that  294.375V is the induced E.M.F. after change in magnetic field.The given parameters;magnetic field strength, B₁ = 0.60 Tand magnetic field strength, B₂=-0.65Tdiameter of the loop, d₂ = 6 cmtime of change, t = 120msThe direction of the current can be determined by applying Flemings left hand rule, as the field points into the paper, the current will be point out of the paper.The magnitude of the induced emf is calculated by applying Faradays law;Emf= - (N×ΔФ)/ΔtEmf= - (N×(B₂-B₁)×(π×d²)/4)/120×[tex]10^{-3}[/tex]Emf=- [(1×(-0.65-0.60))×π×(6×6)/4)]/120×[tex]10^{-3}[/tex]Emf= [(1.25×3.14×36)]/[(4×120×[tex]10^{-3}[/tex])]Emf= [(35.325/480)]×1000Emf= 294.375VHence, the induced E.M.F after changing of magnetic field is 294.375VTo know more about E.M.F, visit here:https://brainly.com/question/27237453?#SPJ4