two point charges of 11 nc each are placed at two of the corners of an equilateral triangle with sides of length 30 cm. what is the electric potential at the unoccupied corner of the triangle?

Using concepts of Electric Potential, we got 6.6μV is the electric potential at the unoccupied corner of equilateral triangle.As we know it the triangle so the distance between charges will be 3cm.we also know that,Electric potential (V):- [1/4πε₀]*[q/r]where; 'q' is charge causing the potential'r' is distance between the charge and the point where the potential is being measured.and 'ε₀' is permittivity of free space.In the given case, the charges are actually at two vertices of an equilateral triangle and the point where potential is being measured is the third vertex.⇒ r =30 cm for both the charges.The first charge is q₁=+11μC and the second charge is q₂=+11C.the magnitude of the total potential:⇒ V=  [([1/4πε₀]*[11/ 30] +  [1/4πε₀]*[(11)/ 30])×100]/1000000000⇒ V= 2 { [1/4πε₀]*[11/ 30] }/10000000⇒ V= 2 { [9 x 10⁹] *[11/ 30] }/10000000        [ because [1/4πε₀] = 9 x 10⁹ ]⇒ V= 2{ [(99/30)] }/10000000⇒ V= 6.6× [tex]10^{-6}[/tex] V or +6.6μVHence, the electric potential at the unoccupied corner of the triangle is 6.6μV.To know more about electric potential, visit here:https://brainly.com/question/12645463#SPJ4