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Using concepts of Momentum, we got 132N is the force exerted by the racket on the ball.Momentum is all about change of velocity with respect to time multiplied by the mass of the object.We have mass of the racket([tex]m_r[/tex])=1000g mass of ball([tex]m_b[/tex])=60ginitial speed of racket([tex]u_r[/tex])=15m/sec initial speed of ball([tex]u_b[/tex])=18m/secfinal speed of ball([tex]v_b[/tex])=40m/sectime of contact(t)=10ms By the law of conservation of momentum:[tex]m_r.u_r+m_b.u_b=m_r.v_r+m_b.v_b[/tex]where [tex]v_r[/tex] is the final velocity of the racket=>1000×15+60×18=1000×[tex]v_r[/tex]+60×40=>1500+1080=1000×[tex]v_r[/tex]+2400=>2580-2400=1000[tex]v_r[/tex]=>[tex]v_r[/tex]=18 mili/secSo the final velocity of the racket=18 mili/secBy the Newton's second law of motion:F=dp/dt------------------eq(1)where:dp = change in momentumdt = change in timeChange in momentum of ball:Δ[tex]_p[/tex]=[tex]m_b.v_b+m_b.u_b[/tex]Δ[tex]_p=(60).(40-18)[/tex]/1000Δ[tex]_p=1.32[/tex]kg m/secUsing eq1,we getF=1.32/0.01=>F=132NHence, the force exerted by the racket exerts on the ball is 132N To know more about momentum, visit here:https://brainly.com/question/24030570#SPJ4(Complete question) is:A tennis player swings his 1000 g racket with a speed of 15.0 m/s. She hits a 60 g tennis ball that was coming towards him at a speed of 18.0 m/s. The ball rebounds at 40.0 m/s. How fast is his racket moving immediately after the impact? You can ignore the interaction of racket with her hand for the brief duration of the collision._________m/s. If the tennis ball and racket are in contact for 10.00 , what is the average force that the racket exerts on the ball?
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