g a coil of 200 turns surrounds a flux of 2mwb produced by a permanent magnet. now the magnet is pushed to the core as shown below causing the flux inside the coil to linearly increase to 5mwb in 100msec. what is the amplitude and polarity of the induced voltage (with respect to the given reference polarity)? briefly explain your answer in words. ans: -60v

Using the concepts of E.M.F, we got 60V is the amplitude of induced voltage and polarity is toward the coil as magnetic flux is increasing.We are given number of turns=200Initial flux(Ф₁)=2mwb=(2/1000)wbWhen the magnet is moving, magnetic flux increases,Therefore, new flux(Ф₂)=5mwb=(5/1000) wb.We know very well from the theory of E.M.F, it is actually change of flux in given time, or e=-dФ/dtwhere negative indicates that voltage is increasing on opposite side.We also have number of turns as 200Therefore, E.M.F induced in magnetic core(e)= -[Number of turns × change in flux]/time duration=>e= - [200×[(5-2)/10000]] / [(1/1000)]=>e= - [200×3×1000]/10000=>e= - (600000/10000)=>e=-60VHence, amplitude of induced voltage is 60V and polarity of induced voltage is opposite of direction of increased magnetic flux..To know more E.M.F, visit here:https://brainly.com/question/27237453#SPJ4