If 100 ml of 3. 0 m solution were diluted to 250 ml, what would the concentration be?.

The concentration after the dilution process is 1.2 M.The process of lowering the concentration of a particular solute in its solution is known as dilution.The formula of dilution is: [tex]V_{1}[/tex] x [tex]M_{1}[/tex] = [tex]V_{2}[/tex] x [tex]M_{2}[/tex], where [tex]M_{1}[/tex] is initial molarity, [tex]V_{1}[/tex] is initial volume, [tex]M_{2}[/tex] is final molarity, and [tex]V_{2}[/tex] is final volume.In this case, we know the values of initial molarity, initial volume, and final volume. So, to know the value of final molarity or final concentration, we could calculate as follows:[tex]V_{1}[/tex] x [tex]M_{1}[/tex] = [tex]V_{2}[/tex] x [tex]M_{2}[/tex] 100 ml x 3 M = 250 ml x [tex]M_{2}[/tex][tex]M_{2}[/tex] = 1.2 MTo know more about dilution, go to:brainly.com/question/15718488#SPJ4