Accepted Answer
The 16-bit operand results in a 2 decrease in ESP. - A 32-bit operand results in an ESP decrease of 4. a pop-up business A value is taken out of the stack.Prior to writing data from the old top of the stack into the destination, the POP ESP instruction increases the stack pointer (ESP). Some debug exceptions are suppressed or prevented by loading the SS register with a POP instruction, and interrupts on the instruction boundary after that are also prevented. The POP instruction reads a byte from the location that the SP register obliquely references. The stack pointer is decremented once the value read is put at the designated address. This instruction has no effect on any flags.Learn more about instruction here-https://brainly.com/question/21507137#SPJ4