a computer is reading data from a rotating cd-rom. at a point that is 0.030 m from the center of the disc, the centripetal acceleration is 120 m/s2. what is the centripetal acceleration at a point that is 0.050 m from the center of the disc?

The centripetal acceleration at the point 0.05m from the center of the CD is 72m/s².The centripetal acceleration of a circular motion is given by,a = v²/rWhere,v is the linear velocity,r is the distance of the particle from the center of the circle,a is the centripetal acceleration.The linear velocity is same for each and every particle.So,v = √(ar)If the acceleration at 0.03m is 120m/s², then the acceleration at 0.050m is,√(120x0.03) = √(a0.05)a = 72m/s².So, the acceleration at a distance of 0.050m is 72m/s².To know more about centripetal acceleration, visit,https://brainly.com/question/22103069#SPJ4