two gliders collide on a frictionless air track that is aligned along the xx axis. glider aa has an initial velocity v0v0 and glider bb is initially at rest. after they collide, aa has a velocity 12v012v0 and bb has a velocity 92v092v0 . find the ratio of the gliders' masses, mambmamb .

The ratio of the mass of the glider a to glider b is 12/91.The law Conservation of Linear Momentum if no external force is working on the body then the linear momentum of the system always remain conserved after and before the collision.Initial Momentum = final momentumOne glider is at rest, let us say its mass is m and one lighter is moving with a velocity V₀ let as say it's mass is M.m(0)+mV₀ = m92V₀+M12V₀m = 92m + 12MDividing the whole equation by m,1 = 92+12M/mm/M = -12/91As we know that mass cannot be negative but in this case the ratio of mass is coming out to be negative.It is not a matter of concern here. It simply means that we have taken the opposite direction of the motion of the gliders. So, we can simply neglect the negative sign here and proceed to our answer as the ratio of the masses of the gliders to be -12/91.To know more about momentum, visit,https://brainly.com/question/402617#SPJ4