A 500-kg cannon fires a 4. 0-kg projectile with a velocity of 500 m/s relative to the ground. What is the recoil speed of the cannon?.

The recoil speed of the cannon is (-4) m/s.How to determine the recoil speed of the cannon?m₁ = 500 kgm₂ = 4.0 kgv₁ = ?v₂ = 500 m/sThe velocity of the cannon and projectile just before the shot is 0v₁ = v₂ = 0The speed of the cannon strike can be calculated by the equation of the law of conservation of momentum, namely∑P = ∑P’(m₁) (v₁) + (m₂) (v₂) = (m₁v₁)’ + (m₂v₂)’(500) (0) + (4.0) (0) = (500) (v₁’) + (4) (500)0 = 500 v₁’ + 2000500 v₁’ = (-2000)v₁’ = (-2000)/500= (-4) m/sSo, the recoil speed of the cannon is (-4) m/s.Learn more about speed here: https://brainly.com/question/28986884#SPJ4