a disk, initially rotating at 114 rad/s, is slowed down with a constant angular acceleration of magnitude 4.94 rad/s2. (a) how much time does the disk take to stop? (b) through what angle (rad) does the disk rotate during that time?

a) if angular acceleration is constantα =Δω/ΔtΔt = Δω/α= (0-114 rad/s)/(-4 rad/s2)= 30sb) Δθ = ωot + 1/2αt2= (120rad/s)(30s) +1/2(-4rad/s2)(30s)2= 3600 rad - 1800 rad= 1800rad.The main difference here is that angular acceleration acts on angular velocity or in vector form. If ω enters the page clockwise, α exits the page counterclockwise. Therefore, if ω is positive, α will be negative. The direction of angular velocity is the direction your thumb is pointing when you bend your finger in the direction of wheel rotation. The direction of angular velocity is always perpendicular to the plane of rotation. The direction of angular velocity is along the axis of rotation. For an object rotating clockwise the angular velocity along the axis of rotation points away from you.Learn more about Angular acceleration here:-https://brainly.com/question/21278452#SPJ4