The partial pressures of ch4, n2, and o2 in a sample of gas were found to be 143 mmhg, 469 mmhg, and 251 mmhg, respectively. Calculate the mole fraction of oxygen.

The mole fraction of oxygen gas, in the sample of the gas is 0.479.Partial pressure of CH₄ = 143 mmHgPartial pressure of N₂ = 469 mmHgPartial pressure of O₂ = 563 mmHgTotal pressure = 1175 mmHgMole fraction = Partial pressure / total pressureMole fraction of O₂ = 563 / 1175Mole fraction of O₂ = 0.479Therefore, the mole fraction of O₂ is 0.479.Mole fraction represents the number of molecules of a particular component in a mixture divided by the total number of moles in the given mixture. It's a way of expressing the concentration of a solution.Learn more about mole fraction here:- https://brainly.com/question/1601411#SPJ4