for any element in keyslist with a value greater than 40, print the corresponding value in itemslist, followed by a comma (no spaces). ex: if the input is: 32 105 101 35 10 20 30 40 the output is:

Import the java.util.Scanner class, as specified in the query.The query makes reference to the public class Arrays Key Value.in the question itself. void public static main (String [] args) ,Final int SIZE LIST = 4 as indicated in the query.How to write the program?in the question itself. void public static main (String [] args)Final int SIZE LIST = 4 as indicated in the query.keysList = new int[SIZE LIST] as specified in the query.itemsList = new int[SIZE LIST] as stated in the question.the citation in the question.In the query, keysList[0] = 13; / is referred to.In the query, keysList[1] = 47; / is referred to.keysList[2] = 71 for each key listed in the query.59; / KeysList is mentioned in the query[3]itemsList[0] = 12; featured in the available answer optionsList[1] in the query equals 36.itemsList[2] = 72 as stated in the query.the following is the response: To access every element of keysList, use the for(i=0;i(keysList.length);i++) /Loop ,array variable. itemsList[3] = 54; /other line to complete the solution..To learn more about program refer to:https://brainly.com/question/28812198#SPJ4