two skaters, both of mass 75 kg, are initially at rest on skates on a frictionless ice pond. one skater throws a 0.3-kg ball at 10 m/s to his friend, who catches it and throws it back at 10 m/s. when the first skater has caught the returned ball, what is the velocity of each of the two skaters?

The velocity of each of the two skaters is 0.04 m/s.Velocity is the directional velocity of a moving object as an indicator of the rate of change of position observed from a particular frame of reference and measured by a particular time standard. Mass of each skater  = 75 kg         mass of the ball = 0.3          velocity of ball = 5 m/s CONCEPT: Due to momentum conservation both gain the same momentum in opposite directionsSOLUTION:  Total momentum in both cases ( throw + return )                                 (P)= (0.3  kg )x 5 m/s + (0.3  kg )x 5 m/s                                    = 3 kg m/sMomentum ( P ) = m vThe velocity of each skater                         V = P / m                                               = ( 3 kg m/s ) / 75 kg                                            = 0.04 m/s  moving apartLearn more about velocity here:-https://brainly.com/question/24445340#SPJ4