9-47 in an elastic collision, a 400.0-kg bumper car collides directly from behind with a second, identical bumper car that is traveling in the same direction. the initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s. assuming that the mass of the drivers is negligible, find the final speeds of both cars relative to the ground after the collision?

The final speeds of both cars relative to the ground after the collision are V₁ = 6 m/s and V₂ = 5.6 m/s respectively.An elastic collision is a collision in which there is no internet loss in kinetic energy within the gadget because of the collision. each momentum and kinetic electricity are conserved portions in elastic collisions.Given;m₁ = m₂ = 400 kgv₁ = 5.6 m/sv₂ = 6 m/sAccording to the law of conservation of momentum,m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂According to the law of conservation of energy,m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2Now, applying the law to momentum and law of conservation of energy,m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂5.6 + 6 = v₁ + v₂ ----------------(1)m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2(5.6)² + (6)² = (v₁)² + (v₂)²67.36 =   (v₁)² + (v₂)² ---------------(2)From equation 1 and 2V₁ = 6 m/s and V₂ = 5.6 m/sAn elastic collision is a come between two bodies in which the full kinetic energy of the two bodies remains equal. In an ideal, perfectly elastic collision, there may be no internet conversion of kinetic strength into other kinds which includes heat, noise, or capacity electricity. Elastic collisions arise whilst both the momentum and kinetic energy are conserved, just like how billiard balls bounce off each different and move at the same speeds as earlier. Inelastic collisions appear whilst simplest the momentum is conserved but not the kinetic power.Learn more about elastic collision here:-https://brainly.com/question/7694106#SPJ4