a motorcycle is rounding a turn on a 30o banked road. the radius of the turn is 90 m, and the coefficient of friction between the road and tire is 0.4. what is the maximum speed she can go without flying outward off the road?

The maximum speed she can go without flying outward off the road is 46.47 m/s.radius of the turn= 90m coefficient of friction between the road and tire = 0.4coefficient of frictionThe ratio between the normal force pressing two surfaces together and the frictional force preventing motion between the two surfaces.it is denoted as[tex]\mu_s[/tex].Mathematically, μs = F/N. where, F is the frictional force and N is the normal force.Then to find out the speed we can calculate it as :[tex]v = \sqrt{ r * g* \mu_s }[/tex][tex]v = \sqrt{ 90* 10* 0.4 }[/tex]v = 46.47 m/s.The maximum speed she can go without flying outward off the road is 46.47 m/s.To know more about frictionhttps://brainly.com/question/27198894#SPJ4