a 75.5 kg solid disk with radius 0.695 m rolls along a horizontal floor so that its center of mass has a speed of 2.80 m/s. how much work must be done to stop it?

The work done must be equal to 211.4 joules to stop it.What does work mean in physics?In physics, work is defined to be the change in energy of a system. Work is given by the symbol W. In its simplest form, work is equal to force times displacement. The total work of the solid disk is defined to be [tex]W=\frac{1}{2}mv^2+\frac{1}{2}I \omega^2[/tex]. That means the total energy of the solid disk is equal to the linear (translational) and the rotational kinetic energies. I = mr² and v = rω so we can simplify the equation to W = mv².We're given that the mass m is equal to 75.5 kg and the velocity v is equal to 2.8 m/s. We can then calculate the total work as follows:W = mv²W = (75.5) (2.8)²W = 211.4The work required to stop the solid disk is confirmed to be 211.4 joules.Learn more about translational kinetic energy here: https://brainly.com/question/8101588#SPJ4